Chosen Solution
So this iPhone in question won’t charge the battery and wont power up unless its plugged in via wall outlet. Ive tested a new battery and new dock connector, still can’t get the battery to charge properly. However, after some looking around I found that some resistors(i think?) near the battery connector seem to have come off. I believe this may be the problem. It seems like the leftmost one has come off and possibly the one next to it as well. You can see them more clearly in the ifixit picture seen here. Im thinking if i can use the circuitwriter pen to try and make jumper or something. Any thoughts? my logic board http://s12.postimage.org/n0rsa0s59/2012_… ifixit picture http://s11.postimage.org/3tzvylmeb/ifixi…
Jose Escobar, all those components are part of your battery connection. So, anything bypassed may lead to errors. we all know how finicky iDevice are when it comes to the battery. your images was a bit hard to interpret, I edited it and added the components to that. The capacitors may be by-passable but I’d be careful with the resistors. Anyhow, just like Mitch said, and I paraphrase, it’s a PITA to solder those back on. You will definitely be good at it before attempting. Hope this helps, good luck.
If you can compare your board with a photo on here and you see something missing then your idea to jump your board with a writer pen is worth a try, its a heck of a lot safer than trying to solder something that small if your not set up, good luck and I want to know how this turns out.
In answer to the original question here—the capacitor that is knocked off in the picture isn’t relevant to the problem, (in my experience). For the original problem, I would look for cold/cracked/lifted solder joints/pads at the connector itself. Identify a lifted pad –repair it by installing a new battery connector and restoring continuity to the pin with no pad from it’s proper trace on the board jessa
“the capacitors may be by-passable” No, it’s the other way around for DC. The caps you may be able to do without, depending on their exact role. The resistors will be by-passable if they are 0 ohms. I guess they must act as some kind of fuse, or place holder for possible future resistors (in later revisions of the phone) that aren’t 0 ohms.
